Question

In figurs 9,AB||DH and BC||FG.If angle ABC =60°,find angle GFH.

Answer 1

As AB II DH
Taking BC as transversal
<ABC=DCE(Corresponding angles)
so, <DCE=60°
<DCE=<BCF(Vertically opposite)
So, <BCF=60°
As BC II FG
Taking CF as transversal
<BCF=<CFG(Vertically opposite)
so, <CFG=60°
Now,<CFG + <GFH=180°{Linear pair}
=>60° + <GFH=180°
=><GFH=180° - 60° = 120°
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