Question

In find the values of x, y and z.
25​

Answer 1

Answer:

But tell the question first........

Answer 2

Answer:

number 2450 in prime factors .

2450 = 2* 1225 = 2*5* 245= 2*5^2 * 29

Possible values :

x=29. y= 5^2 =25 and z= 2

X=29 , y=2 & z =25

(25,29,2) ; (25,2,29) & (2,25,29) & (2,29,25)

x = 58 , y= 25 & z= 1

(58,25,1), (58,1,25) , (1,25 ,58) ; (1,58,25) , (25,1,58); (25,58,1)

x=290 , y=5 and z=1