Question

in finding the HCF of two numbers by division method , the quotients are 1,2 and 3 respectively and the last divisor is 17. find those numbers.
134,175
117,219
119,170
169,210
none​

Answer 1

hey this is an example:-

In finding the HCF of two numbers by division method, the last divisor is 49 and the quotients are 17, 3, 2. Find the two numbers.

In finding the HCF of two numbers by division method, the last divisor is 49 and the quotients are 17, 3, 2. Find the two numbers.243 and 4929

In finding the HCF of two numbers by division method, the last divisor is 49 and the quotients are 17, 3, 2. Find the two numbers.243 and 4929343 and 5929

In finding the HCF of two numbers by division method, the last divisor is 49 and the quotients are 17, 3, 2. Find the two numbers.243 and 4929343 and 5929334 and 5992

In finding the HCF of two numbers by division method, the last divisor is 49 and the quotients are 17, 3, 2. Find the two numbers.243 and 4929343 and 5929334 and 5992None of these

I have searched this from internet there is little bit different in the question.

now u can do it question by this example ok?

Answer 2

Step-by-step explanation:

Divided=divisor×quotint+remainder

17×3+0=51

51×2+17=119

119×1+51=170

So, the numbers are 119,170.