In first mixture, quantity of milk was 6 lit more than that of water. After adding 40 ltr of second mixture (having ratio of water to milk 3:5) in the first mixture, ratio of water to milk in the final mixture becomes 9:13. Find the total quantity of water in the final mixture.
Answers
total final quantity of water is 36 lit
Given : In first mixture, quantity of milk was 6 lit more than that of water. After adding 40 ltr of second mixture (having ratio of water to milk 3:5) in the first mixture, ratio of water to milk in the final mixture becomes 9:13.
To Find: the total quantity of water in the final mixture
Solution:
In first mixture, quantity of milk was 6 lit more than that of water.
Water = x lit
Milk = x + 6 lit
40 ltr of second mixture (having ratio of water to milk 3:5)
3 + 5 = 8
watre = (3/8) * 40 = 15 lit
Milk = (5/8) * 40 = 25 lit
Total water = 15 + x lit
Total Milk = x + 6 + 25 = x + 31 lit
ratio of water to milk in the final mixture becomes 9:13.
=> (15 + x)/(x + 31) = 9/13
=> 195 + 13x = 9x + 279
=> 4x = 84
=> x = 21
total quantity of water in the final mixture. = x + 15 lit
= 21 + 15 = 36 lit
total quantity of water in the final mixture. is 36 lit
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