In flight of 600 k/m, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced to 200 km/hr and the time increased by 30 minutes. Find the duration of the flight.
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Answer:
1 hr
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Step-by-step explanation:
Let the original speed of the aircraft be x km/hr.
then new speed =(x−200) km.hr
Duration of flight at original speed =(600/x)hr
Duration of fight at reduced speed =(600/(x−200))hr
∴600/(x−200) − 600/x= 1/2
⇒ 600x−600(x−20)/(x(x−200)) = 1/2
⇒ 120000/(x²−200x )= 1/2
⇒x²−200x−240000 = 0
⇒x²−600x+400x−240000=0
⇒(x−600)(x+400) =0
⇒x= 600 or x= −400
Ignore negative value
⇒x=600
So, the origianl speed of the aircraft was 600km/hr
hence, duration of flight = (600/x)hr
=(600/60) hr
= 1hr
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