Question

In
fly. ABC is a tringle in which alludes Be
I to side A C and AB are equal
show that AB= AC


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Answer 1

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Answer:

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal)

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° )

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°)

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°) => 2∠B + 2∠DEC = 360°

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°) => 2∠B + 2∠DEC = 360° => ∠B + ∠DEC = 180°

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°) => 2∠B + 2∠DEC = 360° => ∠B + ∠DEC = 180°Also, according to theorem, if opposite angles are supplementary , points are concyclic .

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°) => 2∠B + 2∠DEC = 360° => ∠B + ∠DEC = 180°Also, according to theorem, if opposite angles are supplementary , points are concyclic .Thus, B,C,D,E are concyclic .

Answer:As, opposite angles are supplementary , so B , C , D and E are concyclic .Step-by-step explanation:To prove - B,C,D,E are concyclic .Proof - In Δ ADE AD = AE => ∠ADE = ∠AED (angles opposite to equal sides are equal) Also, ∠ADE + ∠BDE = ∠AED + ∠DEC (Because linear pair is 180° ) => ∠BDE = ∠DEC So , in quadrilateral BDEC ∠B + ∠C + ∠BDE + ∠DEC = 360° (As, sum of angles in quadrilateral is of 360°) => 2∠B + 2∠DEC = 360° => ∠B + ∠DEC = 180°Also, according to theorem, if opposite angles are supplementary , points are concyclic .Thus, B,C,D,E are concyclic .Hence proved .

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