In following figure, ABCD is a rectangle. If E and
Fare mid-points of AD and DC respectively, then
find length of EF.
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Answer:
GIVEN:- ABCD is a rectangle.
E is the mid point on side AD
&F is the mid point on side DC
TO FIND :- length of EF
SOLUTION:- since,
DC=AB=12cm
And DF=1/2DC. ----(Given)
=> DF = 12/2 = 6 cm
Similarly,
DE = 2.5 cm
We know that each angle of rectangle is of 90°. Hence angleEDF= 90°
Now , in ∆DEF
(EF)²=(DF)²+(DE)²
=> EF²=(6)²+(2.5)²
=> EF²=36+6.25
=> EF²= 42.25
=> EF²=4225/100
=> EF=√4225/100
=> EF=65/10
=> EF=6.5cm
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