Question

in following figure seg PS perpendicular seg RQ ,seg QT perpendicular seg PR. If RQ =6,PS=6 and PR then find QT
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Answer 1

Answer:

Solution:

RQ = 6, PS = 6 and PR = 12     ....(given)

area of triangle = 1/2 × base × height

A(ΔPQR) = 1/2 × RQ × PS

∴ A(ΔPQR) = 1/2 × 6 × 6

∴ A(ΔPQR) = 18 unit²

also, A(ΔPQR) = 1/2 × PR × QT

∴ 18 = 1/2 × 12 × QT

∴ QT = 18 / 6

∴ QT = 3

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