Question

in formation of al2o3 from al and o2 ,if 1.5mole of oxygen is used up ,the mass of aluminium that reacted

Answer 1

4Al + 3O2 ---> 2Al2O3 1mole O2 = 32g * 1.5mole = 48g * 2 = 96g Al2O3 = 101.96g/mole * 2 = 203.92g 203.92g - 96g O2 = 107.92g. Therefore, The weight of Al... show more 4Al + 3O2 ---> 2Al2O3
1mole O2 = 32g * 1.5mole = 48g * 2 = 96g
Al2O3 = 101.96g/mole * 2 = 203.92g
203.92g - 96g O2 = 107.92g.
Therefore,
The weight of Al in the reaction of 1.5moles of O2 is 107.92g

Answer 2

Answer:

108g

Explanation:

4Al + 3O2 ---> 2Al2O3 1mole O2 = 32g * 1.5mole = 48g * 2 = 96g Al2O3 = 101.96g/mole * 2 = 203.92g 203.92g - 96g O2 = 107.92g. Therefore, The weight of Al... show more 4Al + 3O2 ---> 2Al2O3

1mole O2 = 32g * 1.5mole = 48g * 2 = 96g

Al2O3 = 101.96g/mole * 2 = 203.92g

203.92g - 96g O2 = 107.92g.=108g(approximately)

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