In four complete revolution of the cap, the distance travelled on the pitch scale is
2mm. If there are 50 divisions on the circular scale, then calculate the least count of
the screw gauge.
ans:0.01 mm
help in process. .....
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Answer:
Circular scale has 50 divisions so one rotation=50 divisions
Thus 4 rotation=200 division
and it is given that 4 rotation=2mm so 200 division=2mm
So least count = 1Division=(2/200)mm=.01mm
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