Question

In four consecutive prime numbers the product of
first 3 prime numbers is 105 and the product of last
three prime numbers is 385 then find that numbers​

Answer 1

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Let the 4 Prime number’s be:- w,x,y,z.

Product of first 3 number’s => w*x*y= 385. (Eq.-1)

Product of last 3 number’s => x*y*z= 1001.(Eq.-2)

Divide equation 2 by equation 1.

x*y*z/w*x*y = 1001/385

(x and y common in both numerator & denominator so remove it).

(1001 & 385 both are divisible by 77 so result is 13/5).

Final equation is:- z/w = 13/5.

Answer:-

Hence the last number “z” is = 13.

And all the Prime numbers are- 5, 7, 11, 13.