Math, asked by mahamimran125, 2 months ago

In four years, a boy will be twice as old as he was 6 years ago. What is his present age?​

Answers

Answered by aaradhyabtsarmy
2

Answer:

Set x = current age

(x+4) is four years from now

(x-6) is six years ago

(x+4) = 2(x-6)

x+4 = 2x -12

add -4 to each side

x = 2x -16

add -2x to each side

-x = -16

x = 16

The boy is 16.

Answered by divineobot5
1

Answer:

8 years

Step-by-step explanation:

let his age six years ago be=x

x+4=2x

(carry x over to the other side)

4=2x-x

4=x

in four years time=2x=2×4=8years.

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