Question

In Freundlich adsorption isotherm x/m = Kp1/n, the value of ‘n’ at low pressure is
(a) more than one.
(b) less than one.
(c) equal to one.
(d) from zero to one.

Answer 1

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Answer 2

Answer:

The correct Option is (c) equal to one.

Explanation:

Freundlich, in 1909 provided an empirical relationship between the amount of gas adsorbed by the unit mass of solid adsorbent and the pressure at a particular temperature. The equation which represents their relationships are as follows:

                           

                            $x/m=kp^1^/^n$

Where x represents the mass of the gas adsorbed on mass m of the adsorbent at pressure p. k and n are constants that depend on the nature of the adsorbent and the gas at a particular temperature.

For the validity of this equation at low-pressure n is always equal to 1.

                             

                              $x/m\propto\ kp$

Hence, the correct option is (c) equal to one.