Question

In game of chance the probability of winning is 1/3 . What is the probability of losing

Answer 1

Hey mate ☺

$p(e) + p(not \: e) \: = 1 \\ \frac{1}{3} + p( \: not \: e) = 1 \ \\ p \: ( \: not \: e \: ) = 1 - \frac{1}{3} \\ p (\: not \: e \:) = \frac{2}{3}$

Hope it helps you ☺✌✌

Answer 2

The probability of losing is $\frac{2}{3}$

Step-by-step explanation:

Given :In game of chance the probability of winning is 1/3 .

To Find :What is the probability of losing?

Solution :

Probability of winning =$\frac{1}{3}$

We know that Sum of probabilities is 1

So, Probability of losing =$1- \frac{1}{3}$

                                        =$\frac{2}{3}$

Hence The probability of losing is $\frac{2}{3}$

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In game of chance the probability of winning is 1/3 . What is the probability of losing

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