In garden there are some rows and columns. The number of trees in a row is greater than number of trees that in each column by 10. Find the number of trees in each row if the total number of trees are 200
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Hi there
Here's the answer:
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Let No. of trees in a row = r
and No. of trees in a column = c
Given,
r = c+10.
Total No. of trees = 200.
We have,
r × c = 200 -------(1)
=> (c+10) × c = 200
=> c² +10c -200 = 0
Solve for roots
=> c² + 20c - 10c - 200 = 0
=> c(c+20) -10(c+20) = 0
=> (c-10)(c+20) = 0
=> c = 10 or -20
c can't be -ve
•°• c = 10
substitute in (1),
r × 10 = 200
=> r = 20
•°• No. of trees in each row = 20.
& No. of trees in each column = 10
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Verification:
20 × 10= 200
and 20- 10 = 10
Data matched
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
©#£€®#
:)
Hope it helps
Here's the answer:
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Let No. of trees in a row = r
and No. of trees in a column = c
Given,
r = c+10.
Total No. of trees = 200.
We have,
r × c = 200 -------(1)
=> (c+10) × c = 200
=> c² +10c -200 = 0
Solve for roots
=> c² + 20c - 10c - 200 = 0
=> c(c+20) -10(c+20) = 0
=> (c-10)(c+20) = 0
=> c = 10 or -20
c can't be -ve
•°• c = 10
substitute in (1),
r × 10 = 200
=> r = 20
•°• No. of trees in each row = 20.
& No. of trees in each column = 10
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
Verification:
20 × 10= 200
and 20- 10 = 10
Data matched
•°•°•°•°•°•<><><<><>><><>°•°•°•°•°•
©#£€®#
:)
Hope it helps
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