Question

in geometric progression t2=3/5;t3=1/5.then the common ratio is​

Answer 1

Answer:

Common ratio r= 1/3.

Step-by-step explanation:

We know that in GP successive terms has a common ratio between them;

$a, \: ar, \: a {r}^{2}, \: a {r}^{3} ...$

in GP ,with common ratio r.

In geometric progression;

Second term and third terms are

$t_2 = \frac{3}{5} \\ \\ t_3 = \frac{1}{5}$

then the common ratio is

$r = \frac{t_3}{t_2} \\ \\ r = \frac{ \frac{1}{5} }{ \frac{3}{5} } \\ \\ r= \frac{1}{3}$

Hope it helps you.