Question

in geometric progression the 4th term is 8 and the 8th term is 128​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

t4=8

t8=128

a+3d=8 (1)

a+7d=128 (2)

by elimination method we get,

4d=120

d =30

now putting the value of d in the first eq. we get,

a+3(30)=8

a=8-90

a=-82

hope this ans helped you