Question

In giren figures AP and Ag ane langents of PAq: 20, Then poq. ? 160 (bj 180' (C) 90 d 40
pa= qa(radius of circle)
po=qo(radius of circle)
OPA=90
OQA=90
OA=OA( common side)
OpA+OQA+POQ=360
90+90+POQ=360
180+POQ=360
POQ=360-180
hence poq =160.​

Answer 1

Answer:

[tex]Given, PQ is a chord of a circle with center O. 

Also, ∠QPT=60°.

Let x be the point on the tangent PT.

∠QPT+∠OPT=90

⇒∠OPT=300−∠QPT=900−600=300

In ΔPOQ 

∠POQ=180−(∠OPQ+∠PQO)=180−30−30=1200

Minor arc ∠POQ=1200

Therefore Major arc ∠POQ=3600−1200=2400

Angle subtended by  an arc at centre is double the angle subtended by it on remaining part of circle

∴∠QRP=21∠POQ=1200

Step-by-step explanation:

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