Question

in give fig: ab=bc , angle abo=cbo , prove that angle dab=ecb​

Answer 1

Step-by-step explanation:

first congruent bother triangles oba and obc

ab =bc ( given)

ob = ob ( given)

angle abo= angle cbo ( given)

therefore triangle oba congruent to obc

therefore angle ocb= angle oab

since od and oa is a straight line

angle ocb + angle bce = 180 and

angle oab + angle bad =180

now since both angle ocb and oab are equal therefore angle bce and bad are equal