Question

In give figure expansion of spring will be :-
(take g = 10 m/s^2)

(1) 64 cm
(2) 16 cm
(3) 32 cm
(4) None

Answer 1

Answer:

1

Explanation: From NLM..

In case of 4kg block

mg-T=ma

40-T=8

T=32N

Tension in spring 2T=64

T=kx

K=100N/m

K=64

Answer 2

Answer:

Tension of the spring is $64 \ cm$

Explanation:

Given: Image is given as an attachment

To find: Tension of the spring

Solution:

By applying Newton's law of motion,

Consider the case of $4 \mathrm{~kg}$ block,

$m g-T=m a$

thus,

$\begin{aligned}&4 \times 10-T=4 \times 2 \\&40-T=8 \\&T=32 \mathrm{~N}\end{aligned}$

Tension in spring is,

$\begin{aligned}&T^{\prime}=2 T=32 \times 2=64 \mathrm{~N} \\&T=k x \\&k=100 \mathrm{~N} / \mathrm{m} \ldots(\text { from diagram }) \\&64=100 \times x \\&x=\frac{64}{100}=0.64 \mathrm{~m}=64 \mathrm{~cm}\end{aligned}$