Question

In given circuit calculate voltage across a-b
1) 10V 2)20V
3) 30V 4)40V​

Answer 1

Answer:

I think that

2) 20v

is correct

Explanation:

and if it is right then mark me as a brainlist and thank my answer

Answer 2

Answer:

As the diode is treated ideal, its forward resistance `R_(f) = zero`. It acts as short circuit. So `10 k Omega` is in parallel with `15 k Omega` and the effective resistance across `AB` is

`R_(AB) =(10 xx 15)/(10+15)=(10 xx15)/(25) =6k Omega`

`6 k Omega` is in series with `5 kOmega`

`:.` total resistance

`= R_(T) = 6 k Omega + 5 k Omega = 11 k Omega`,

`V=30 V`. Current drawn from the battery is

`I=(V)/(R_(T))=(30V)/(11 k Omega) =2.72 mA`

`V_(AB) =IR_(AB)=2.72 mA xx 6k Omega = 16.32 V`.

Explanation:

Hop it helps