Question

in given circuit diagram two resistors are connected to a 5V supply. Answer the following questions​

Answer 1

Answer:

(a). Here, Equivalent Resistance of R1 and R2 is 14Ω

Then, I = V/R

I = 5/14

and, V = IR

V = 5/14 ×8

V = 2.85V

Hence, Potential difference across 8Ω resistor is 2.85V

(b). Lets third resistor be R, using trial method put the value of R =4Ω then

Equivalent resistance of second and third resistor is 0.41Ω

Since, potential difference of 6Ω resistor is dropped from 6Ω to 0.41Ω therefore, potential difference of 8Ω will be smaller