Question

In given circuit potential difference across 4 ohm is?
please explain it ​

Answer 1

We know that.....by the ohm's law

V = IR

there's,

I = 0•8A

R1 = 1/3+1/6 =1/2 = 0•5 ohm

R2 = 4 Ohm

so R = R1 + R2

=0•5 + 4 = 4•5

if we put the value in ohm's law...

Potential difference V= 4•5×8

=3•6 Volt