In given circuit R = 100ohm . If voltage leads current by 60° then find -
(a)
Current supply by source.
(b)
Average power
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Answer:
Power factor = Cos phi = R/Z
phi = 60°
1/2 = R/Z
Z = 2R
Z =impedence = 200ohm
Current = V/Z
Currentmax= 200/200
Irms = peak/√2
Irms = 1/√2
Power = i^2 R
P = 50watt
or
Power
Vrms Irms Cosphi
200√2 × 1/√2 × 1/2
50watt
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