In given fig a circle touches the side BC of triangle ABC at P and touches AB and AC produced at Q and R .If AQ=5cm find the perimeter of triangle ABC.
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Answer: 10cm
Step-by-step explanation:
perimeter of triangle ABC =AB+BC+AC
therefore, perimeter of triangle ABC = AB+BP+PC+AC
BP=BQ [tangents from an external pt. B on the circle]------(1)
AQ=AB+BQ=5cm
FROM EQ(1)
AB+BP=5cm
similarly,
AC+CR=AR=5cm
[AQ=AR as they are tangents from an ex. pt. A]
therefore,
AB+BP+PC+AC=10cm
Well done
Tq
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