In given Fig, AB and CD are parallel lines intersected by a transversal PQ at L and M respectively, If ∠CMQ = 60o
, find ∠ LMD, ∠LMC and ∠ DMQ in the figure.
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Step-by-step explanation:
<CMQ=<LMD (vertically opposite angle)
60°=<LMD
<LMD+<LMC=180°(linear pair)
60°+<LMC=180°
<LMC=180°-60°
<LMC=120°
<DMQ=<LMC (vertically opposite angle)
<DMQ=120°
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