in given fig.abcd is a square, find x
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Since diagonal bisects the vertex of a square,
anOCE = anOCD = 45
anDOA + anAOE = 180
anDOA = 180 - 120 = 60
anDOA = anCOE = 60. (vertically opposite)
In triangle COE
anOCE + anCOE + x = 180
x = 180 - 45 - 60
x = 75
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Angle DOC=120°(vertically opposite angle)
Angle DOC+angleCOE= 180° (Linear pair)
AngleCOE=60°
Similarly, angleDOA=60°
angle DOA= angleOCE (alternative interior angle)
angleOCE=60°
angleCOE+angleOCE+x=180(angle sum property of triangle)
60°+60°+x=180°
120°+x=180°
x=180°-120°
x=60°
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