Question

In given fig triangle ABC BD perpendicular AC prove that
AB²+CD² = AD²+ BC²​

Answer 1

Answer:

Step-by-step explanation:AB2=BD2+AD2

BD2=BC2-CD2

So,AB2=BC2-CD2+AD2

AB2+CD=AD2+BC2

Answer 2

Answer:

solution:-

In triangle ABD,

we know,

By pythagoras theorem

AD^2+BD^2=AB^2 - (I)

Similarly,

In triangle CBD,

By pythagoras theorem

CD^2+BD^2=BC^2 - (II)

Subtracting equation (I) and (II)

AD^2+BD^2-CD^2-BD^2=AB^2-BC^2

AD^2-CD^2=AB^2-BC^2

AD^2+BC^2=AB^2+CD^2

AB^2+CD^2=AD^2+BC^2