in given fig x:y:z:=1:3:5
Find x,y,z
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Angle COB = 90
Angle AOC= 180 -90 (linear pair)
= 90°
x + y + z = 90 ( angle AOC)
Let x= 1a
y=3a
z=5a
a + 3a + 5a = 90
9a = 90
a=10
Thus angles x = 10 , y(3×10)=30 and z(5×10)=50
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...Hope it helps....
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Answer:
Angle COB = 90
Angle AOC= 180 -90 (linear pair)
= 90°
x + y + z = 90 ( angle AOC)
Let x= 1a
y=3a
z=5a
a + 3a + 5a = 90
9a = 90
a=10
Thus angles x = 10 , y(3×10)=30 and z(5×10)=50
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