Question

in given figure 10.50 three arms BA and BC of triangle ABC are respectively parallel to a meeting and EF of angle DS prove that angle abc + d f is equal 180 ​

Answer 1

Answer:It's given that AB||ED And EF || BC

We'll do a little construction here and extend the lone ED and BC until they intersect at point G

Now,

As EF||BC,

And here BG is is acting as a transversal,

Therefore,

∠ EGB = ∠ DEF (by alternate interior ∠s) -----(i)

Now,

AS AB|| ED

Then,

∠ ABC + ∠ EGB = 180° (interior angles on thr same side of transversal).---(ii)

By substituting for EGB of eq (i) in eqe (ii).

It becomes,

∠ABC+∠DEF= 180°.

Step-by-step explanation: