Question

In given figure 7,   1  2 & ΔNSQ  ΔMTR then prove that Δ PTS ~ ΔPRQ. (CB

Answer 1

Answer ✒ in the attachment below

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Answer 2

Answer:

given: ∠1=∠2 ;  ΔNSQ≅ΔMTR

to prove: ΔPTS≈ΔPRQ

proof: ∠1=∠2 [given]

∴PS=PT [sides opposite to equal angles are equal]  →(1)

∠Q=∠R [cpct of ΔNSQ≅ΔMTR]

∴PQ=PR [sides opposite to equal angles are equal]  →(2)

devide (1) and (2)

PS/PQ = PT/PR [equals devided by equals the wholes are equal] →(3)

∴ In ΔPTS and ΔPRQ

∠P=∠P [common]

PS/PQ = PT/PR [ from (3)]

∴ ΔPTS≈ΔPRQ (SAS similarity rule)