in given figure AB||DC, Angle BDC is 30° and Angle BAD is 80° then find angle,x,y&z
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Answered by
121
x is 30 alternate angles
30 +80+y is 180
y = 180 -110=70
30 +y-30+z=180
30+70-30+z=180
z=180-70=110
30 +80+y is 180
y = 180 -110=70
30 +y-30+z=180
30+70-30+z=180
z=180-70=110
Answered by
46
∠x = 30°, ∠y = 70°, ∠z = 110°
Step-by-step explanation:
As we know,
AB║DC
so,
X = 30° (∵ Alternate angles are equal)
In ΔABD,
∠A + ∠B + ∠D = 180° (∵ sum of the three angles of the triangle)
80° + 30° + ∠D = 180°
∠y = 180° - 110°
Y = 70°
In ΔBDC,
30° + y-30° + Z = 180° (∵ angle sum property)
30° + (70° - 30°) + ∠C = 180°
Z = 180° - 70°
Z = 110°
Learn more: Find the required angles
brainly.in/question/16405530
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