Question

in given figure, AB II CD determine angle BOC

Answer 1

Hello user

AB II CD

So,

130° = angle BOC + 70°

angle BOC = 60°

Answer 2

Hey mate .......

here is ur answer......

Angle SOB + Angle BOC + Angle COT = 180° ( linear pair..

70° + Angle BOC + Angle COT = 180°

Angle C + Angle COT = 180°

130° + COT = 180°

180° - 130° = 50°

70° + Angle BOC + 50° = 180 ......linear pair

Angle BOC = 180 - ( 70 + 50)

180- 120 = 60 °

Hence proved...

Hope it helps

Be brainly