Math, asked by tarunjadon96, 11 months ago

In given figure, AB is diameter of circle AC = 6 cm. and BC = 8 cm., then find
area of shaded part.​

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Answers

Answered by rajtelecome60
5

Step-by-step explanation:

in triangle acb ac=6cm, BC=8cm, angle c 90°

ab^2=bc^2+ac^2=64+36=100cm

ab=√100

ab=10cm

a=8cm

b=6cm

c=10cm

s=(a+b+c)/2=(8+6+10)/2=12cm

area of triangle acb = √12(12-8)(12-6)(12-10)

=√12×4×6×2

=√4×3×4×2×3×2

=4×3×2

=24cm^2

in circle d=10cm

r=5cm

area of circle =πr^2=22/7×5^2=550/7cm^2

area of shaded region =area of circle-area of triangle

=550/7-24cm^2

=(550-168)/7cm^2

=382/7cm^2 is write answer

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