In given figure, AB is diameter of circle AC = 6 cm. and BC = 8 cm., then find
area of shaded part.
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Step-by-step explanation:
in triangle acb ac=6cm, BC=8cm, angle c 90°
ab^2=bc^2+ac^2=64+36=100cm
ab=√100
ab=10cm
a=8cm
b=6cm
c=10cm
s=(a+b+c)/2=(8+6+10)/2=12cm
area of triangle acb = √12(12-8)(12-6)(12-10)
=√12×4×6×2
=√4×3×4×2×3×2
=4×3×2
=24cm^2
in circle d=10cm
r=5cm
area of circle =πr^2=22/7×5^2=550/7cm^2
area of shaded region =area of circle-area of triangle
=550/7-24cm^2
=(550-168)/7cm^2
=382/7cm^2 is write answer
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