Question

In given figure ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that (i) ar(BDE) = 1/4 ar(ABC) (ii)ar(BDE)= 1/2ar(BAE) (iii)ar (ABC)=2 ar(BEC) (iv)ar(BFE)=ar(AFD) (v)ar(BFE)=2ar(FED) (vi)ar(FED)=1/8ar(AFC)

Answer 1

here is your answer

I hope it will help u