Question

in given figure ∆ABC , DE||AC , if DC || AP , where point P lies on BC produced , then prove that

BE/EC = BC/CP​

Answer 1

Answer:

this is the correct diagram and sol.

Answer 2

Prove$BE/EC=BC/CP$

Step-by-step explanation:

Given:

The given figure shows that Δ$ABC$

$DE$║$AC$, $DC$║$AP$

The point $P$ lies on $BC$.

To find:

To prove that $BE/EC=BC/CP$.

Formula used:

Basic proportionality theorem

Solution:

In Δ$BPA$

We know that $DC$║$AP$

So, by the basic proportionality theorem, we have,

$BC/CP=BD/DA$  ⇒ $(1)$

Now in Δ $BCA$

we know that $DE$║$AC$

So, by the basic proportionality theorem, we have,

$BE/EC=BD/DA$ ⇒ $(2)$

From the equation (1) and (2) we get,

$BE/EC=BC/CP$

Hence we proved $BE/EC=BC/CP$

#SPJ2