Question

in given figure ABCD is a rectangle whose diagonals AC and BD intersect at O if angle at a b is equal to 32° find 1 ∠ABC 2 ∠DCB

Answer 1

Angle BAD =90 (Abcd is the rectangle)

Angle cad =angle - 28

90-28

=62

Angle cad = 62

Now

In triangle cad and dbc

Angel ADC=angle bcd(each 90)

Ab=bc( opposite sides of rectangle)

CD=DC

So triangle cad congruent triangle dbc

By SAS criteria

DBC=CAD(cpct)

DBC=62

Angle =62