Question

In given figure ABCD is a square and P is the midpoint of AD. BP and CP are joined. Prove that
∠ PCB = ∠ PBC. ​

Answer 1

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In triangle PAB and PDC.

PA = PD (given )

AB =CD(SIDE OF A SQUARE)

<PAB =PDC =90° (By R.H.S ,PAB =PDC

Therefore,PC = PB ---> <PCB =<PBC

Hope it helps ❤

Answer 2

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In given figure ABCD is a square and P is the midpoint of AD. BP and CP are joined. Prove that ∠ PCB = ∠ PBC.

⇛In triangles PAB and PDC,

• PA = PD (given)
• PA = PD (given)
• PA = PD (given) AB = CD (side of square)
• ∠ PAB = ∠ PDC = 90° (By RH'S, ∆PAB ≅ ∆ PDC )
• ∴ PC = PB ⇒ ∠ PCB =∠ PBC

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