Question

In
given figure, ABllCD and
EFIIDG Find angle GDH , angle AED and
Angel DEF​

Answer 1

Step-by-step explanation:

As, AB//CD (Given)

Therefore,

Angle CDH = Angle AED = 40°

( Corresponding Angles)

Now,

Angle AED + Angle FED + Angle BEF = 180°

( Linear Pair)

So, 40° + FED + 45° = 180

FED = 180 - (40+45) = 95°

Also, EF//DG (Given)

Therefore,

Angle HDG = Angle DEF

(Corresponding Angles)

Angle HDG = Angle DEF = 95°

HOPE IT HELPS!