in given figure ABPC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as a diameter .Find the area of the shaded region.
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ar of quadant =154cm2. ar of triangle = 94cm2 ar of semicircle = 308cm2. ar of shaded reason =ar(semicircle) - ar qudant -ar of triangle. =308 - (154-98)
= 308-56
= 302 cm2
= 308-56
= 302 cm2
threefriends:
308-56 is it?
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