In given figure, angle ABC =69°, angle ACB = 31°, find angle BDC.
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In∆ BAC 69+31+ angleBAC =180
Angle BAC=100
Angle BAC=angle BAD(angle in the same segment)
Angle BAD= 100
Angle BAC=100
Angle BAC=angle BAD(angle in the same segment)
Angle BAD= 100
Answered by
14
Hello mate =_=
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Solution:
∠ABC+∠ACB+∠BAC=180°
⇒69°+31°+∠BAC=180°
⇒∠BAC=180°−69°−31°=80° ........(1)
∠BAC=∠BDC (Angles in the same segment are equal) .......(2)
From (1) and (2), we can say that
∠BDC=80°
hope, this will help you.
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