Question

in given figure angle bec=135° and angle ecd =25° find angle bac​

Answer 1

Answer:

Angle BAC=half of angle BEC

135/2=74.5

(angle subtenant by chord at centre is double of angle at any point of circle)

Answer 2

Answer:

110

Step-by-step explanation:

given angle BEC=135°

and angle ECD=25°

Now, ang ABD=ACD (angles in the same ssgment)

ABD=25°

AEC =180 (straight line...)

180-135=45° (linear pair)

Ang AEB=45°

180-(45+25)= 180-70=110=Ang BAC

hope it helps.... Pls mark me the brainliest..