Question

in given figure AOB is diameter of circle & P is any point on the circle find ∆ APB
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Answer 1

Answer:

In the given circle,

AOB is the diameter and P is any point on the circle.

Therefore arc APB forms a semicircle and angle APB is inscribed in it

We know that, any angle inscribed in a semicircle measures 90°.

Therefore ∠APB measures 90°.

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Answer 2

Answer:

AOB is the diameter and P is any point on the circle

.

. . arc APB forms a semicircle and angle APB is inscribed in it

angle of semicircle is right angle

APB =90