Question

In given figure bc is a diameter . If AB =3cm AC = 4 cm and angle A = 90° find the area of the shaded region


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Answer 1

Given,

AB = 3 cm

AC = 4 cm

According to Pythagoras theorem,

BC sq = AB sq + AC sq

BC sq = 3 sq + 4 sq

BC sq =  25

BC = root 25 = 5 cm

SO ,

radius of circle is 5/2

area of circle = pi r sq = 22/7 * 5/2 * 5/2 = approx 19.625 cm sq

area of triangle = 1/2 * 4 * 3 = 6 cm sq

Area of shaded region = area of circle - area of triangle

                                      = 19.625 - 6

                                      = 13.625 cm sq

Answer 2

HERE IS YOUR ANSWER

Given:

In triangle ABC ,

AC = 4cm , AB =3cm and A= 90

By Pythagoras thereom

BC^2= AC^2 + AB^2

= 3^2 + 4^2

= 9+16 = 25

BC = √25

BC = 5

Area of triangle ABC= 1/2 base × height

= 1/2 ×3×4

Area of triangle ABC = 6cm

Area of circle = πr^2

= 22/7 × 5/2 × 5/2

= 275/ 74

= 19.625

Therefore Area of shaded region = area of circle - area of triangle

= 19.625 - 6

= 13.625cm

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