Question

In given figure BP perpendicular AC, CQ perpendicular AB A-P-C , A-Q-C are similar

Answer 1

Answer:REF. Image.

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ]      [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c  [common]

and BC=BC  [common]

∴ΔBCP≃ΔBCQ  [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]

Step-by-step explanation: