Question

In given figure current through circuit is?
please explain​

Answer 1

Answer:

plzz draw the fig. neatly I don't understand it properly.

Answer 2

Answer:

Pls tell the voltage properly. I assume its 4V..... :(

Explanation:

If my assumption is correct...... let's head to the question

Now, in conductor AB....

we have 2 resistors in series

By series formula.....

$r = r1 + r2 + .......$

Now....

resistance = 1 + 2 = 3ohm.....

Now resistor AB and 9ohm resistor are connected in parallel... so,

$\frac{1}{rp} = \frac{1}{r1} + \frac{1}{r2} .....$

So we get resistance as

$\frac{1}{3} + \frac{1}{9 } = \frac{4}{9}$

$rp = \frac{9}{4} = 2.25 \: ohm$

Total resistance =

$rt \: = 3 + 2.25 = 5.25$

Now,

$r = \frac{v}{i}$

so,

$5.25 = \frac{4}{i} \\ i = \frac{4}{5.25 } = 0.79 \: ampere$

Hope this helps ..... :)