Question

In given figure, how much energy is absorbed by

electrons from the initial state of no current (ingore

thermal motion) to the state of drift velocity ? Number

of electrons per unit volume = 1029 m–3, length of

circuit = 10 cm, cross-section area = 1 (mm)2.,​

Answer 1

The drift velocity of the electron is Vd = 1 / 1.6 x 10^-4 m/s .

Explanation:

The relation between current and drift velocity is given by;

I = ne Avd   -----(1)

According to ohm's law;

I = V / R

I = 6 V / 6 ohm

Now rearranging the equation (1)

Vd = I / neA   ----(2)

Now substitute the value in the equation (2)

Vd = 1 / 10^29 x 6 x 10^-19 x 10^-6

Vd = 1 / 1.6 x 10^-4 m/s

Thus the drift velocity of the electron is Vd = 1 / 1.6 x 10^-4 m/s

Answer 2

Explanation:

Given In given figure, how much energy is absorbed by electrons from the initial state of no current (ingore  thermal motion) to the state of drift velocity ) Number  of electrons per unit volume = 1029 m–3, length of  circuit = 10 cm, cross-section area = 1 (mm)2

• So in which form the electrons absorb energy, so it will be kinetic energy.
• So kinetic energy K.E = ½ mv^2
• So I = v/R
•       = 6/6
•       = 1 A
• Therefore I = neAVd
•           So Vd = 1 / neA
•                      = 1 / 10^29 x 1.6 x 10^19 x (10^-3 m)^2
•            So Vd = 10^-4 / 1.6 m/s
• So K.E = ½ x total mass Vd^2 (total mass = me x nAL)
• So K.E = ½ me x nAL Vd^2
•            = ½ x 9.1 x 10^-31 x 10^29 x 10^-6 x 0.1 x (10^-4 / 1.6)^2
•          = 1.77 x 10^-17 J

Reference link will be

https://brainly.in/question/11717659