In given figure , if AP = PB , then prove that AC = BC.
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Hence, we have PB = BR
According to the given condition, we have AP = PB
From the above equations, we get
AP = BR …… (1)
Now, using the same property of tangents as above, we have
AP = AQ …… (2)
On equating the R.H.S. of equations (1) and (2), we get
AQ = BR …… (3)
Similarly, using the same property of tangents as above, we have
QC = RC …… (4)
On adding equations (3) and (4), we get
AQ + QC = BR + RC
AC = BC
In this way, we find that AC = BC.
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