In given figure lines ab,cd,ef intersecting at o find the vaules of x,y,zand it is being given that x:y:z=2:3:5
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Answered by
2
We have ∠1 = 70°
∠1 = ∠3 (Vertically opposite angles)
Therefore, ∠3 = 70°
Now, ∠1 = ∠5 (Corresponding angles)
Therefore, ∠5 = 70°
Also, ∠3 + ∠6 = 180° (Co-interior angles)
70° + ∠6 = 180°
Therefore, ∠6 = 180° - 70° = 110°
∠1 = ∠3 (Vertically opposite angles)
Therefore, ∠3 = 70°
Now, ∠1 = ∠5 (Corresponding angles)
Therefore, ∠5 = 70°
Also, ∠3 + ∠6 = 180° (Co-interior angles)
70° + ∠6 = 180°
Therefore, ∠6 = 180° - 70° = 110°
Answered by
1
Y= Cof (v.o.a)
now
x+y+z=180(angles on a straight line)
now let x =2x
y=3x
z=5x
2x+3x+5x=180
10x =180
x=18
2x=36
3x=54
5x=90
I hope it help you
now
x+y+z=180(angles on a straight line)
now let x =2x
y=3x
z=5x
2x+3x+5x=180
10x =180
x=18
2x=36
3x=54
5x=90
I hope it help you
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