Question

In given figure, <ACB = 40 find <OAB

Answer 1

ACB is A Triangle
In Triangle sum of Total angle=180°
If 40° is given
Then Subtract it from 180=140
Now divide 140 in two part means angle A and angle B=70°
Now O is bisector That divides angle in two equal parts means angle A in oab =35°
Angle OAB=35°